№8
Замена всех вхождений подстроки в строке
(defun replace-all (string part replacement &key (test #'char=))
"Returns a new string in which all the occurences of the part
is replaced with replacement."
(with-output-to-string (out)
(loop with part-length = (length part)
for old-pos = 0 then (+ pos part-length)
for pos = (search part string
:start2 old-pos
:test test)
do (write-string string out
:start old-pos
:end (or pos (length string)))
when pos do (write-string replacement out)
while pos)))
(replace-all "Groucho Marx Groucho" "Groucho" "ReplacementForGroucho")
; "ReplacementForGroucho Marx ReplacementForGroucho"
Источник:
cl-cookbook.sourceforge.net
cl-cookbook.sourceforge.net